max r =88 |
送交者: zhf 2019月09月30日19:55:23 于 [灵机一动] 发送悄悄话 |
回 答: 趣味的数学-95 由 gugeren 于 2019-09-28 08:18:35 |
解: (w,3)/(w+r)=p; (w+1,3)/(w+1+r)=p(1+1/3) (4/3)w(w-1)(w-2)/[(w+r)(w+r-1)(w+r-2)]= (w+1)(w)(w-1)/[(w+r+1)(w+r)(w+r-1)] 4(w-2)(w+r+1) = 3(w+1)(w+r-2) w^2 - w -2 = 11r - wr r = (w^2 - w -2)/(11 - w) (1) 从(1)得出,w < 11 max r = 88 |
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