| A 赢的概率 |
| 送交者: 车五进二 2019月10月03日15:20:34 于 [灵机一动] 发送悄悄话 |
| 回 答: 能否解释P\'(A) = P(A) + P(T) / 2 由 zhf 于 2019-10-03 12:14:56 |
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P'(A) is the probability that A has more heads than B after throwing N+1 coins. If A already had more heads than B with the first N coins, then the extra coin doesn't matter, if A tied with B on the first N coins, then there's 1/2 chance that the last coin is a head and therefore A will have more heads than B with N+1 coins. Thus P'(A) = P(A) + P(T)/2 |
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