| 答案 |
| 送交者: 车五进二 2019月10月24日21:31:27 于 [灵机一动] 发送悄悄话 |
| 回 答: 趣味的数学-115 由 gugeren 于 2019-10-20 10:01:18 |
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From the 2 equations, we have a^2 >= 8b and b^2 >= a, therefore b^4>=a^2>=8b, hence b^3 >= 8, therefore, b >= 2, and a >=4. Since both a = 4 and b = 2 are achievable, therefore min(a+b) = 6. |
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