| 答案 |
| 送交者: 車五進二 2019月10月24日21:31:27 於 [靈機一動] 發送悄悄話 |
| 回 答: 趣味的數學-115 由 gugeren 於 2019-10-20 10:01:18 |
|
From the 2 equations, we have a^2 >= 8b and b^2 >= a, therefore b^4>=a^2>=8b, hence b^3 >= 8, therefore, b >= 2, and a >=4. Since both a = 4 and b = 2 are achievable, therefore min(a+b) = 6. |
|
|
|
|
 | |
|
 |
| 實用資訊 | |
