| 那这不更简单？ |
| 送交者: 田苗 2008月11月27日12:04:57 于 [灵机一动] 发送悄悄话 |
| 回 答: This is my code 由 零加一中 于 2008-11-27 10:59:45 |
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array y{9}; /* Input are y(1) ... y(9)*/
array x{9}; do i = 1 to 9; x(i) = 0; end; do i = 1 to 9; If x(y(i)) != 0, there is repeat. x(y(i)) = 1; end; |
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| 实用资讯 | |
